Other Parts Discussed in Thread: SN74LV240A, SN74LS240
Tool/software:
I want to use it in this combination. Please tell me how to consider about Input transition.
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Tool/software:
I want to use it in this combination. Please tell me how to consider about Input transition.
I understood that the combination is fine. How do I know output transition rate of SN74LV240A is faster than 5 ns/V?
No; the 100 µA value is specified only to show that small currents result in small voltages, but the limit is the worst case for the lowest supply voltage, so it is not realistic for 5 V.
0.55 V / 16 mA ≈ 34 Ω.
Sorry, it was Rout not Ron.
"0.4V / 8mA ≈ 50Ω" is suticker than 34Ω in this caluculation.
Still, when calculating Rout, is it okay to use the value that is closer to Vcc?
There was a worse combination. This combination is not good, right?
LS240 cannot be changed because it is the board on the other side.
Rout depends on the supply voltage, so you should use only the nearest VOL/VOH specification.
The outputs of TTL devices do not behave like CMOS outputs. As shown in figure 21 of the SN74LS240 datasheet, there are a 50 Ω resistor and a Darlington transistor (which should not affect the drive strength).
Please note that the output of a TLL device is not compatible with a 5 V CMOS input (VOH is below VIL(min)). The supply on the SN74LVC8T245's input side would have to be 3.3 V or less. (A 3.3 V signal is compatible with a TTL input.)
The LS output does not behave like a CMOS output, so you cannot use all these formulas.
You can assume that a LS output pulls up with about 50 Ω to about 3.5 V. This is more than enough for any CMOS input.
New PCB receives signals from two types of boards.(PCB-A and PCB-B)
Is this combination OK?
The input leakage current of CMOS inputs is extremely small, so those VOL/VOH limits do not matter; the actual output voltages will be near GND/VCC.
This will work.