TMS320F28335: The problem of calculation method of electric angle.

Green Deng

Part Number: TMS320F28335

Dear all:

One of my customer has a question about calculation method of electric angle.

v.ElecTheta = (v.PolePairs*v.MechTheta) -floor(v.PolePairs*v.MechTheta); /* Q24 = Q0*Q24 */

In the above procedure, why is the electric angle calculated in this way?

Just multiply the polar logarithm by the mechanical angle? What does it mean to subtract another floor (v.polepairs * v.mechtheta) from the program?

Best regards

over 5 years ago

0 Yanming Luo over 5 years ago

TI__Guru** 116400 points

The range of both electrical and mechanical angles are _IQ(0.0) to _IQ(1.0), so you need to use this equation to ensure the electrical angle is between _IQ(0.0) to _IQ(1.0). For example, the mechanical angle is _IQ(0.6) and pole-pairs is 4, the electrical angle equals to "(_IQ(0.6)*4 - 2)=_IQ(0.4)".

0 user6222596 over 5 years ago in reply to Yanming Luo

Prodigy 10 points

thank you very much, I have already understood it！

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TMS320F28335: The problem of calculation method of electric angle.