CCS/TMS320F28388D: FLASH Api function

Nagesh,

It can be that the other core is still owning the semaphore.

When a given core fails to gain access to semaphore, please check the value of the semaphore in the register window to know which core owns it (if CPU1 has to claim it, CPU2 and CM should relinquish the semaphore).

Thanks and regards,
Vamsi

hi Vamsi, 

I did debug further to understand the issue here is what i observed, I am using only cpu1 for now.

1. Called flash erase to the erase the flash before writing, here i had set the flash pump to CPU1 .

#define FLASH_PUMP_KEY                  0x5A5A0000UL //!< Pump semaphore key

EALLOW;

IPC_PUMPREQUEST_REG = FLASH_PUMP_KEY | 2;

EDIS;

2. the release the pump semaphore after the flash erase is complete

EALLOW;

IPC_PUMPREQUEST_REG = FLASH_PUMP_KEY;

EDIS;

After the releasing teh pump semaphore the PUMPREQUEST did not change the value to zero , it was still retaining the value which was set by flash_claimsemaphore.

can you let me know why the flash release semaphore was not successful.

thanks,

Nagesh

Nagesh,

Could you confirm that the value 2 went through for instruction IPC_PUMPREQUEST_REG = FLASH_PMP_KEY | 2;?  

Did it work fine when you use the flash programming example from C2000Ware?

Thanks and regards,

Vamsi

Hi Vamsi, 

Yes when given a value of 2 it worked fine , and i did try the example code it works fine there.

i have observed a different behaviour.

The PUMREQUEST register shows up a value of 2 which never got cleared when set to zero, but when i try to re assign it to 2 it just keeps looping the while loop and never comes out of it though since it is set to 2.

seems like the register value is holding some value which we are not able to see.

EALLOW;
while(IPC_PUMPREQUEST_REG != (uint32_t)wrapper)
{
IPC_PUMPREQUEST_REG = FLASH_PUMP_KEY | (uint32_t)wrapper;
}
EDIS;

thanks

Nagesh

Nagesh,

Thank you for the info.

What are CPU2 and CM doing when this happens?  Are they halted or executing some code? Please halt them and see how it behaves.

What value does it read back when you issue a CPU read to semaphore?  (I understand register window is showing 2).

Could you send me a sample project (please remove any proprietary code) so that I can try it on my side?

Thanks and regards,
Vamsi

Hi Vamsi, 

I tried to modify the example program but its working fine there, but my actual code is not working.

will it be possible to have a desktop sharing session with you so that i can show you the actual problems in it 

let me know you available time or you can schedule a meeting according to your free time in Microsoft Teams meeting.

thanks,

Nagesh

Hi Vamsi, 

I also observed a strange behavior , i basically wanted to see the value of the register in the expression window

#define IPC_PUMPREQUEST_REG \
IPC_Instance[IPC_CPU1_L_CPU2_R].IPC_Boot_Pump_Reg->IPC_PUMPREQUEST

EALLOW;
while(IPC_PUMPREQUEST_REG != (uint32_t)FLASH_CPU1_WRAPPER)
{
IPC_PUMPREQUEST_REG = FLASH_PUMP_KEY | (uint32_t)FLASH_CPU1_WRAPPER;
}
EDIS;

I have given the variable in expression window as 

IPC_Instance[0].IPC_Boot_Pump_Reg->IPC_PUMPREQUEST to observe its value but it does not recognize it in my application. But the same variable in Example code gets recognised what could be the reason.

Nagesh,

This does not seem like a flash issue. I will ask our SW team to help you further if you want to have a session.

Regarding the register read, did you try to directly read the register address location?

Thanks and regards,

Vamsi