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CCS/MSP430FR5857: Timer PWM when stopped should give high on pin.

Part Number: MSP430FR5857

Tool/software: Code Composer Studio

#include <msp430.h>
#include <stdint.h>

int main(void)
{


    WDTCTL = WDTPW | WDTHOLD;               // Stop WDT

    // Configure GPIO
    P1DIR |= BIT0 | BIT1;                   // P1.0 and P1.1 output
    P1SEL0 |= BIT0 | BIT1;                  // P1.0 and P1.1 options select
    P1SEL1 &= ~(BIT0 | BIT1);
    PJSEL0 |= BIT4 | BIT5;

    // Disable the GPIO power-on default high-impedance mode to activate
    // previously configured port settings
    PM5CTL0 &= ~LOCKLPM5;

    /* operation beyond 8MHz _before_ configuring the clock system.*/
    FRCTL0 = FRCTLPW | NWAITS_1;

    /* Clock System Setup*/
    CSCTL0_H = CSKEY >> 8;                    /* Unlock CS registers*/
    CSCTL1 = DCORSEL | DCOFSEL_4;             /* Set DCO to 16MHz*/
    CSCTL2 = SELA__LFXTCLK | SELS__DCOCLK | SELM__DCOCLK; // Set ACLK = XT1; MCLK = DCO
    CSCTL3 = DIVA__1 | DIVS__1 | DIVM__1;   // Set all dividers
    CSCTL4 &= ~LFXTOFF;
    do
    {
        CSCTL5 &= ~LFXTOFFG;                // Clear XT1 fault flag
        SFRIFG1 &= ~OFIFG;
    } while (SFRIFG1 & OFIFG);              // Test oscillator fault flag
    CSCTL0_H = 0;                           // Lock CS registers

    // Configure Timer0_A
    TA0CTL |=TACLR;
    TA0CCR0 = 16000-1;                        // PWM Period
    TA0CCTL1 = OUTMOD_1|CLLD_1;                    // CCR1 reset/set
    TA0CCR1 = 8000;                           // CCR1 PWM duty cycle
    TA0CTL = TASSEL__SMCLK | MC__UP; // ACLK, up mode, clear TAR

    __bis_SR_register(LPM3_bits);           // Enter LPM3
    __no_operation();                       // For debugger
}

This is the code I am thinking of basing the next code I am writing.

What I want to know is if when I stop Timer A0 by writing

TA0CTL| = MC__STOP;

will the output at TA0.1 be high or low or will it depend on what level the PWM is on.

I want to write code so that it stays high whenever TimerA0 is stopped.

Thank you in advance.

Viswanath.

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