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DRV8428E: locked out or damaged? chip does not reset on power cycle acts dead

Part Number: DRV8428E
Other Parts Discussed in Thread: DRV8428
using the DRV8428E. in the following configuration:
1-VM=+12Vdc, 16-nSleep=+3.3Vdc, 11-DECAY/TOFF=GND,R1=10k,R2=3.3K,Vref=~.8188V.
Using the following truth table:
truth table
After several attempts of stepping the driver goes dark and no longer works. This is now the second chip that I have experienced this. resetting power does not rest the chip; it appears to be locked out or damaged. On the second chip I also tested prior to installing the motor with four led's to show the polarity of both bridges and this worked fine until the motor was connected then a repeat result of the first test. my co-worker has also now had 5 chips stop working in the same conditions using various vref values. Please advise on how to proceed.
Thanks in advance.
  • Hey Mitch,

    That device should be plenty capable of spinning that stepper motor, agreed. 

    Is this on your own board or one of our EVMs? Do you have one of our EVMs you could test with?

    Best,

    Jacob

  • we are using are own breakout board with the bottom pad attached to gnd and then installed on a bread board.

  • Hey Mitch,

    Ahh okay, is it a generic HTSSOP-24 breakout board?  

    Our device needs a few of the capacitors to be located as close to the device as possible.  If it is a breakout board on a breadboard then these caps are relatively far from the device, and this could cause some noise or ringing that damages the device.  

      

    Also, what is the full part number on your device?  This device has a few orderables that often get confused (along with normal DRV8428), please confirm that you have DRV8428E as the device marking on the top of your device.  Reason being E vs P vs 8428 each support a different control scheme.  

    And did you order these through either TI or an authorized distributor?  Want to make sure not counterfeit devices.  

    Ordering an EVM is probably your best approach to test the device to its full potential.  You can remove any of the 0-ohm resistors to the left of the header pin and then use jumper wires to jump in your own signal to the device pins. 

    Best,

    Jacob