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TPS7B7702-Q1: [TPS7B7702QPWPRQ1] Circuit review and inquiries

Part Number: TPS7B7702-Q1

Hi, TI support Team

I have received inquiries about the current circuit diagram and TPS7B7702QPWPRQ1 product from customers.

Since it was received as an Excel file and the file contains circuit diagrams and questions,

please let us know the email of the person in charge so we can deliver it.

Please provide the email of the person in charge.

Thanks.

Regards,

MJ

  • Hello,

             Excel files can be shared in E2E posts, would you be comfortable in sharing it here? Thanks!

    Regards,

    Srikanth

  • Hi, Srikanth

    I'll share the file here.

    If there are 3 sheets in the excel file, the same question also exists.

    As the customer company is requesting a reply as soon as possible, we are sorry, but we ask for your confirmation as soon as possible.

    TI_LDO_TPS7B7702QPWPRQ1_Circuit Review Request_210906.xlsx

    Thanks.

    Regards,

    MJ

  • Hello Jeon,

                      I am looking into this, I will get back to you by the end of the day tomorrow. 

    Regards,

    Srikanth

  • Hello Jeon,

                     The excel sheet you attached had three sheets and , as you mention, the questions seemed to be identical. Please find below my responses to the questions:

    (1) Range of Voltages on SENSE pin:

    (a) For over current fault condition, as mentioned in the datasheet snapshot you attached in the Excel file, the SENSE pin voltage varies from 2.4V (Min) to 2.65V (Max) and would typically latch to 2.55V

    (b) For Normal load currents, as mentioned in the datasheet snapshot, the VSENSE pin assumes a voltage of (IO*RSENSE)/CURRENT_RATIO, where CURRENT_RATIO is the ratio of IOUT and ISENSE and is typically 198 in value. The Electrical Characteristics table (6.5) of the datasheet in page 6, provides the accuracy of the CURRENT_RATIO (OUTx to SENSEx current ratio accuracy) for various load currents. For example, a load current of 60mA would result in CURRENT_RATIO having an accuracy of ±5%. The accuracy of CURRENT_RATIO along with the accuracy of the resistor can be used to determine the range of voltage on the SENSE pin. 

    (c) For no load current, I am running a simulation to determine the CURRENT_RATIO accuracy for your specific choice of resistor divider values (22KOhm, 5.6KOhm). I will provide you the results by the end of the day tomorrow.   

    (2) Diode requirement: The device has reverse current (short to battery) protection built-in. Hence strictly speaking, the external diode is not required. 

    (3) LDO1 & LDO2 Interaction:

    (a) LDO1 and LDO2 are operate fairly independent of each other (except for thermal shutdown). 

    (b) If output of LDO1 results in Thermal shutdown, then both outputs (that of LDO1 and LDO2) will shut down. But for other faults (Current limit, short to Battery), fault on one LDO output will not impact the output of the second LDO.

    (c) The governing thermal equation remains : TJ = TA + θJA* (P1 + P2), where TJ is the junction temperature, TA is the ambient temperature, θJA is the thermal resistance and P1 and P2 are the power dissipated in LDO1 and LDO2 respectively. To prevent thermal shutdown TJ needs to be less than 175°C. Short circuit/Over Current in one LDO output does not necessarily result in thermal shutdown, but if it does, disabling LDO1 would remove P1 and help bring the part out of Thermal Shutdown. It would not be required to disable LDO2.  As the equation suggests it depends on the values of P1, P2, TA and θJA.    

    (4) Fault Conditions: In case of thermal shutdown, the output of both LDO channels will disable once TJ exceeds ~175°C. When TJ reduces in temperature by ~15°C, the outputs will turn on again. Here toggling of EN pin is not required. When reverse current fault occurs however the ERR_N asserts Low. To remove this latch condition, the fault (reverse current) condition must be removed and the EN pin must be toggled

    (5) Overall Circuit review: I think the values of the resistors and capacitors chosen look good. I do not understand what empty terminal treatment means, could you please explain what that term means?

    I hope this helps with what you were looking for. Let me know if you have more questions. Thanks!

    Regards,

    Srikanth

  • Hi, Srikanth

    Thank you for your kind reply.

    I answer your questions above.

    This is a question about NC pin (Not used pin).

    I would like to inquire additionally about the questions the customer has.

    Please tell me how to set each level in the table below.

    Thanks.

    Regards,

    MJ

  • Hi, Srikanth

    Please answer the above questions.

    For the simulation case, please confirm and answer LDO1 and LDO2.

    Additional inquiries have been received and will be contacted.

    The figure below is the inquiry from the 3rd sheet of the excel file that was delivered previously.

    Questions that are different from those listed in the 1st and 2nd sheets are listed.(Red text)

    Please reply on this matter.

    Thanks.

    Regards,

    MJ

  • Hi, Srikanth

    Is the review of the circuit diagram you answered previously confirmed for the three circuits?

    I know you are busy, but I would like to answer the above questions as quickly as possible.

    Thanks.

    Regards,

    MJ

  • Hello Jeon,

                      I apologize for the delay in getting back to you. I am not sure how I missed answering your question or providing you the simulation data I collected. I am looking into your question, please provide me a day, I will get back to you by the end of the day tomorrow at the latest. Thanks!

    Regards,

    Srikanth

  • Hello Jeon,

                       You mentioned that there is a question on the NC pin, but I could not find it. Regarding setting the voltage level on the SENSE pin, as was mentioned, it depends on the value of the load current. VSENSE pin assumes a voltage of (IOUT*RSENSE)/CURRENT_RATIO. In sheet 1 &2 the typical value of IOUT is given to be 60mA and RSENSE has been selected to be 2KΩ. For this magnitude of IOUT, the typical value of CURRENT_RATIO is 198 and it varies by 5% (provided in table 4 of Datasheet). Hence for 60mA of load current, the voltage on the sense pin would typically be ~600mV (with max and min values of ~640mV and ~580mV respectively). In sheet 3 the typical IOUT is 8mA and 49mA for LDO1 and LDO2 respectively. The corresponding sense voltage would typically be ~80mV (Max ~100mV, Min ~68mV) and ~500mV (Max 550mV, Min 450mV) respectively. 

                       Regarding the No-load condition, there is still an output current given by VFB/RFB. For the circuit in Sheet 1 for example, RFB is selected to be 5.6kΩ and since VFB is 1.2V, the load current is ~220uA. For this load current we simulated the SENSE pin output current to typically be ~1uA. Hence the voltage on the SENSE pin would be ~2mV (for RSENSE of 2KΩ).

                        Regarding the question on Page 3, apologies for my oversight. Yes, even if the load current on the LDO is 1mA, we can accurately detect the fault conditions. The current limit can be set externally using RLIM = (1.233*198)/ICURRENT LIM. In sheets 1-3, it looks like 910Ω and 1.2KΩ have been selected which result in current limits of ~270mA and 200mA respectively. To maintain the accuracy, it would be best to set this current limit to at least 50mA. The resistors and capacitor values selected for all three circuits look good. Thanks!

    Regards,

    Srikanth 

  • Hi, Srikanth

    1. Rsense setting for MIC consumption current (3rd sheet)

    As specified in the spec, the current consumption of the Mic is Min 0.4mA, Max 1.2mA.

    Considering the above current, it seems that there is no problem even if Rsense resistance is applied up to 390kohm to distinguish between Open Load and

    Normal conditions.

    Are those values appropriate?

    2. If you look at the table below, the Current Sense Accuracy standard for a current of 5mA or less is not shown.

    Is there no Current Sense Accuracy information at Min 0.4mA, Max 1.2mA?

    Please share.

    Thanks.

    Regards,

    MJ

  • Hello Jeon,

                      I am looking into this, please provide me two days to get back to you with required information. Thanks!

    Regards,

    Srikanth

  • Hello Jeon,

                      Yes, even if RSENSE of 390KΩ was selected, you will be able to distinguish between the open load and normal load conditions since the resulting voltage levels on the Sense pin will be sufficiently distinct. 

                      Regarding the current sense accuracy information at load currents of 0.4mA and 1.2mA, please note that it is not a tested parameter. Simulation results for room temperature suggests that for load current of 0.4mA, the mean and sigma of the distribution of the Current_Ratio (ILOAD/ISENSE) are 210.8 and 21.6 respectively. For load current of 1.2mA, the mean and sigma of the Current _Ratio distribution are 202.6 and 7.55 respectively. Assuming 3*sigma event to be worst case scenario, the accuracy for 0.4mA and 1.2mA load currents at room temperature are ~30% and ~11% respectively. Please note that these numbers are specific to the circuit setup provided in sheet 3 of the document. I hope this was the information you were looking for, let us know if you have more questions. Thanks!

    Regards,

    Srikanth  

  • Hi, Srikanth

    Thank you for reply.

    I have additional inquiries from our customers.

    Please answer about Rsense and Current Sense Accuracy under the conditions below.

    Low temperature: -40 degrees

    High temperature: +85 degrees

    Thanks.

    Regards,

    MJ

  • Hello Jeon,

                      I can provide you this data by the end of Tuesday next week (19th Oct). 

    Regards,

    Srikanth

  • Hello Jeon,

                      Simulations suggest the following numbers about the Current Sense ratio:

    (a) At -40°C

         (1) Load Current of 400uA: Mean= 207, Sigma = 23.3, Accuracy (at 3 sigma) = 33.7%

         (2) Load Current of 1.2mA: Mean = 201.2, Sigma = 8.35, Accuracy (at 3 sigma) = 12.4%

     (b) At 85°C      

         (1) Load Current of 400uA: Mean= 213.2, Sigma = 21, Accuracy (at 3 sigma) = 29.5%

         (2) Load Current of 1.2mA: Mean = 203.5, Sigma = 7.18, Accuracy (at 3 sigma) = 10.6%

    Thanks!

    Regards,

    Srikanth