We are using TPS62065QDSGRQ1 part in our design and whose output we are using to charge a supercapacitor. When there is no output from the regulator at the absence of input voltage to regulator and enable is below 0.4V, Supercap will provide the required voltage to the circuit.
As now Regulator has no input voltage and enable is low, We are providing a 4.2 V power at out pin of the regulator. Which is resulting a voltage at input pin of the regulator, which is 0.5V lesser than the voltage present at output pin.
Please, Let us know whether this has any affect on the operation of the TPS62065QDSGRQ1 regulator and whether this has any affect on regulator life or other parameters.