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UCC21540: How to select a gate driver?

Part Number: UCC21540
Other Parts Discussed in Thread: UCC23513

1.What is the difference between current-on and voltage-on gate drivers?

2.How do I choose between current-on or voltage-on gate drivers?For example, ucc21540 is voltage-on, whereas ucc23513 requires an IF greater than a value to be on.

  • Hi Hailan,

    1. Most of our gate drivers turn on with a voltage at the input. This is what voltage-on refers to. Whereas for current-on, a current needs to be flowing through to turn on a device. This is mainly use for older opto compatible inputs. 

    2. The UCC21540 has input pins for A and B channel and a DIS pin as well. It is TTL and CMOS compatible threshold logic that is typically controlled by a 3.3V or 5V MCU. The UCC23513 on the other hand is opto compatible as it uses an emulated E diode, giving it an anode(pin 1) and cathode(pin 3). It is the only isolated gate driver in our portfolio that works like this. Since it acts as a diode, a voltage is applied to the anode with respect to the cathode and a current IF flows into the E diode for operation.

    When it comes to selecting a driver, I recommend first deciding between a dual channel driver(like the UCC21540) or a single channel driver(like the UCC23513). If you would like to use a single channel driver and want opto compatibility(usually used with older optocoupler based devices), you can go with the UCC23513 (current-on). If you do not need opto compatibility, I would recommend the UCC53xx family. 

    Please let me know if you have further questions.

    Regards,

    Akshat

  • Thanks Akshat ! I have another question, is it true that an isolated drive of current-on type can reduce noise interference from the input signal?

  • Hi Hailan,

    For current on or voltage on, the noise can be reduced as long as the schematic and layout recommendations are followed. There are recommendations in section 11 of the datasheet that gives the best recommendations to to reduce noise at the input pins. Hope this helped!

    Regards,

    Akshat