Other Parts Discussed in Thread: LM5050-2
Hi,
I used two N-MOSFET on my power board, one N-MOSFET works as an ideal diode( I used a LM5050-2 to work with N-MOSFET), one N-MOSFET works as a load switcher. but I have concern of how much current can go through the MOSFET without damaging the N-MOSFET, so I did a simple testing: I connected a E-LOAD to Drain pin of the N-MOSFET (ideal diode) to draw current from 1A-10A, then tested the temperature of the N-MOSFET to check if there is a hot issue happened, I found the MOSFET did't heat at all even at 10A current load, I don't understand why it is not hot at all.
My question is how I should to do calculation of the power consumption of the MOSFET?
1:I measured the voltage difference between the SOURCE and DRAIN with a digital multimeter, the voltage difference is very smaller, it is about 0.1V, assume the voltage difference is 0.1V,current is 10A:
P=0.1V*10A=1W ?
OR
2:P=I*I*Rds(on)=10A*10A*0.058ohm=5.8W ?
When N-MOSFET works as an ideal diode, the current flows from SOURCE to DRAIN, is the Resistance between SOURCE and DRAIN is the same as Rds(on) at the situation when the current flow from DRAIN to SOURCE?
Thanks
Kelvin