This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

TPS631010: Designing with TPS631010YBGR

Part Number: TPS631010

Hello Team,
I am using the buck-boost converter TPS631010YBGR in one of our projects.
The input voltage is 3V from a LiMnO2 primary battery.
The required output voltage is 1.8V at 100mA.
The 1.8V is to power an MCU.
The MCU will be in sleep mode most of the time and the power consumption will be less than 400uA.
To measure the power consumed by the MCU alone we are planning to give a 1.8V output of the TPS631010YBGR keeping the regulator disabled and no voltage at the input of the TPS631010YBGR.
The TPS631010 doesn't have an active discharge circuit.
So this procedure may not damage the IC.
Can you please comment on this?

Also, the IC has a feature of Reverse Current Operation.
Can anyone please explain what is Reverse Current Operation?
Does this mean if there is no voltage at the input and if a voltage is present at the output of the regulator, the regulator will reverse boost/Buck the voltage?

Also what will happen to the Reverse Current Operation if the chip is disabled?

Looking for your reply

  • Hi Vijay,

    About the consumption test of MCU, it should be ok. a kind remind that there is a 2uA smaller leakage current with device. 

    Reverse current only happen in FPWM mode and when device is enabled. When device is enabled and work in FPWM mode, if the Vout is higher than target, device will try to regulate the output voltage by sinking current from output.