UCC28064A: UCC28064A

Sam Abeysekera

Prodigy 115 points

Part Number: UCC28064A

Hi Ulrich

Ref PMP30763 Rev_C PFC Schematic.SchDoc

1. What is the purpose D14 ? is this for protection ?

Please advice

Regards

Sam

over 1 year ago

0 Mike O' over 1 year ago

TI__Guru* 79386 points

Hello,

I am reviewing your inquiry and will get back to you shortly.

Regards,

0 Mike O' over 1 year ago in reply to Mike O'

TI__Guru* 79386 points

Hello,

I reviewed that circuit and it looks like the diode D14 is used bypass R80 and R82 when discharge C64. This will give a faster discharge of C64 which would have been 5*(R80+R82)*C64 limited for discharge.

Regards,

0 Sam Abeysekera over 1 year ago in reply to Mike O'

Prodigy 115 points

Hi Mike

Thanks for the help

Ref PMP30763 Rev_C PFC Schematic.SchDoc

1. D15 cathode connected to C15 cannot discharge?

2. What is the purpose of D1 & D5 ? is this to rectified again? or when C1 get discharged voltage want to come back to the rectifier?

Please advice

Regards

Sam

0 Sam Abeysekera over 1 year ago in reply to Sam Abeysekera

Prodigy 115 points

Hi Mike

Thanks for the help

Ref PMP30763 Rev_C PFC Schematic.SchDoc

1. D14 cathode connected to C64 cannot discharge?

2. What is the purpose of D1 & D5 ? is this to rectified again? or when C1 get discharged voltage want to come back to the rectifier?

Please advice

Regards

0 Mike O' over 1 year ago in reply to Sam Abeysekera

TI__Guru* 79386 points

Hello,

I am reviewing your inquiry and will get back to you shortly.

Regards,

0 Mike O' over 1 year ago in reply to Mike O'

TI__Guru* 79386 points

Hello,

1. C64 is charged and discharged with a 12 V supply. To reset this circuit C64 needs to be discharged. The only reason I could see for the need of diode D14 was to discharge C64 faster by bypassing resistors R80 and R82.

2. Diodes D1 and D5 are boost diodes.

Regards,

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UCC28064A: UCC28064A