Hi TI’s Experts:
Here is a Webench Design link of LM5023: webench.ti.com/.../SDP.cgi
The circuit working conditions are described as follows: Input normal voltage is 58V;Output Voltage is 125V and maximum output Current is 0.3A. The recommended transformer turns ratio is Np:Ns:Naux=24:60:6, and According to my personal deduction, the peak current on the primary side is about 4 amps.
Q1:How to Calculate the peak current of AUX windings? in my opinion: At the beginning of OFF Time, the current of AUX windings is equal to Np*Ipri(peak)/Naux, which is about 16 amps. This is abnormally large.
- If I am wrong, please point out my problem.
- If I am right, please tell me how the energy(or Current) in OFF Time is divided between the secondary and auxiliary windings.
Q2: Ropto. I think the resistance's power rating Which is 50mW is too small.
Look forward to your kind reply.