Tool/software:
Hi Team,
Please could you advise.
The datasheet for BQ2970 states that
" Over-discharge detection (VUVP) is defined as the voltage between BAT and VSS at which the DSG drive
output goes from high to low by reducing the V1 voltage. V1 is set to 3.5 V and gradually reduced while V2 is
set to 0 V. The over-discharge release voltage is defined as the voltage between BAT and VSS at which the
DOUT drive output transition from low to high when V1 voltage is gradually increased from a VUVP condition.
The overcharge hysteresis voltage is defined as the delta voltage between VUVP and the instance at which
the DOUT output drive goes from low to high."
Also
If a charger is connected to a battery in over-discharge state and the voltage detected at the V– is lower than
–0.7 V, the device releases the over-discharge state and allows the DOUT pin to go high and turn ON the
discharge FET once the battery voltage exceeds over-discharge detection voltage (VUVP)
Question.
Am i correct in thinking that there are two conditions where the Over-Discharge state wil be released?
The reason I ask is that I have a single cell protected by BQ2970. When a load (50mA) is applied to the pack the cell will discharge to Vuvp and DOUT goes low diconnecting the load.
If the load is physically disconnected the Over-Discharge condition will release without being connected to a charger?
Many thanks.
