Other Parts Discussed in Thread: BQ34Z100EVM, BQSTUDIO, EV2400
Tool/software:
In the BQ34Z100EVM circuit, the BQ34Z100-R2 IC burned out. We're trying to figure out what happened. We've noticed that the source that goes into the REGIN, when we have a voltage above 5V, which is our case, the voltage varies between 3V6 and 4V7. We don't understand why. We are already in the process of buying a new EVM for testing.
Our test situation: 02 lead-acid batteries connected in series. The voltage varies from 20V to 28V8. Jumpers configured as follows: J1 closed. J2 selected "32V". J3 is set to "A". On J5 we have 02 jumpers at ">5V". We left J6 in the "EXT" position and tested it; we also changed the selection on J6 to "A" and "B" at the same time and tested it.
Questions: 1) What voltage does the EVM put on the REGIN pin for voltages above 5Vdc? 3V6 ? 4V?
2) The battery voltage is measured at the BAT pin, right?
3) You need the divider for voltages above 5Vdc, but in this case the resulting voltage from the divider to the BAT pin would reach a maximum of 0.8564V (32V selected). With the battery ranging from 20V to 28V8 on the BAT pin, we get 0.5353V to 0.7708V. 3a) Is the voltage really that low? 3b) How can we get the display to show 20000(mV) instead of 850(mV)?
4) We want to use the same circuit on our board as on the EVM, as shown in the drawing below. Does this work?
5) In Table 5-1, pins "P1" and "P2" are marked as connected to VSS when not in use. Is this correct? Aren't we short-circuiting them? Or can we leave them open? Or do we need a pull-down resistor?
Thank you in advance for your reply.
Sincerely, Mauricio
