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TPS2HCS10-Q1: TPS2HCS10-Q1 Current Consumption Inquiries

Chae Hui Cheon
Prodigy 50 points

Part Number: TPS2HCS10-Q1

Tool/software:

Hello
I wonder the current consumption of TPS2HCS10-Q1 by mode.

Below is the applied voltage of our controller.
- VBB : 12V / VDD : 5V

In the table above, I am inquiring as follows.

 

1. MCU ON, TPS2HCS10-Q1 OUTPUT ON

  • 2mA + 2.75mA = 4.75mA

2. MCU OFF, TPS2HCS10-Q1 OUTPUT ON

  • 1.5mA + 2.75mA = 4.25mA

I understand that the IC maintains the output even if the MCU is turned off.

When it's 5V, all IQ conditions say that the diagnostic function is disabled, so it's a little confusing.

What is the consumption current when the diagnostic function is activated?

Is my calculation correct?

  • 0
    TI__Mastermind 33610 points

    Hi Chae,

    Yes, your calculations are correct.

    Yes, the device maintains the output if the MCU loses power, provided that VDD is still powered, the watchdog is disabled (to prevent watchdog failure due to MCU not working), and the MCU losing power does not trigger a Limp Home failure (which would be determined by your application implementation). If the Limp Home mode occurs, you can program the device to keep the current output state.

    The VDD = 5.5V spec for IVBB is in juxtaposition to the one directly below it, with VDD = 3V and diagnostics are off. Following that logic, the IVBB when VDD = 5.5V and diagnostics are on would be less than when VDD = 3V and diagnostics are on, the last row in the picture.

    Thanks,

    Patrick

  • 0 in reply to Patrick Shalton
    Prodigy 50 points

    Hello

    So under the condition that TPS2HCS10-Q1 maintains normal output, the lowest power mode consumes 4.25mA?
    I would like to ask if OUTPUT cannot be maintained with less current consumption.
    (VBB : 12V / VDD : 5V)

  • 0 in reply to Chae Hui Cheon
    TI__Intellectual 875 points

    Hi, Patrick

    I can't catch the sentence you commented.

    "The VDD = 5.5V spec for IVBB is in juxtaposition to the one directly below it, with VDD = 3V and diagnostics are off. Following that logic, the IVBB when VDD = 5.5V and diagnostics are on would be less than when VDD = 3V and diagnostics are on, the last row in the picture."

    I think datasheet explained that IVDD (VDD=5.5V, Diag=On) would be higher than IVDD (VDD=3.0V, Diag=On), but you mentioned "~~would be less than when VDD = 3V~~"

    Can you also clarify this?

  • 0 in reply to Luke Park
    TI__Mastermind 33610 points

    Hi Chae,

    The device has a low power mode (LPM) which can be used to greatly reduce the Iq. In LPM, the output stays high but the device on resistance is increased. Please read more about LPM in the data sheet to see if it can work for all or part of your application.

    Hi Luke,

    Yes, that was my mistake, sorry about that. I had focused on IVBB - when VDD = 5V, IVBB is lower but IVDD is higher than when VDD = 3V - and accidentally typed about IVBB rather than IVDD. Yes, you are correct, IVDD is higher at VDD = 5V than when VDD = 3V so that would extend when diagnostics are enabled as well.

    Thanks,

    Patrick