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LM1117: TO-252

Part Number: LM1117

Tool/software:

Hi,

my question is in regard to thermal resistance data specified on page 4 of the datasheet for LM1117 800-mA, Low-Dropout Linear Regulator. An image is shown below. As you can see for TO-252 package, junction to case resistance is specified as 52.1 C/W while Junction to ambient is at 45.1 C/W. How the junction to case thermal resistance be higher than that of junction to ambient. same scenario is for TO-263. Could you please clarify? Thanks. 

  • Hello Mojtaba, 

    Thank you for your question! 

    Please see the [FAQ] Thermal Dissipation from an LDO Perspective, question 5 (also below). HERE

    5) A) Why do different parts in the same packages have different thermal values when comparing different metrics? B) Similarly, when comparing two different packages, why does one have a better R_θJA, but a worse R_(θJC(top)) value?

    A) When looking at different packages, a device could have an improved thermal pad design but have more mold compound between the top of the die and the top of the package. This may result in a lower R_θJA and a higher R_(θJC(top)) (recall that R_(θJC(top)) thermal resistance assumes all the heat is transferred through the top of the case, which is a bad assumption).

    B) R_θJA & R_(θJC(top)) values are greatly dependent on die size, thermal pad of the package, and the die’s vertical (z location) within the mold compound. The most effective path for removing heat is usually a thermal pad which is a slug of metal on the bottom of the package soldered to the PCB. A thermal pad allows the entire surface area of the die to more efficiently conduct heat to the PCB which lowers junction temperature and lowers R_θJA.

    Hope this helps! 

    McKyla

  • Hi McKyla,

    Thanks for taking the time to respond to my question. Your response answered my question. I have another question if you do not mind. For the package I am looking at NDP-TO 252, junction to case and junction to board thermal resistances are given as 52.1 and 29.8 C/W indicating lower thermal resistance to the bottom. The junction to top and junction to board characterization parameters however indicates the opposite with PSI-JT and PSI-JB being 4.5 and 29.4 C/W with the junction to top having a lower resistance. I do know that the techniques in getting these variables are different but they give two opposite impression. In my case, I have measured the case temperature and I am interested in estimating the board temperature. what would you suggest to do?

    This is what I was thinking was the right way: With PD= 0.8*1.3=1.04V ((Vin-Vout)*Iout) , PSI-JT = 4.5C/W, and Tc= 96C,  TJ is estimated at 96+4.5*1.04=100.7C. Then with PSY-JB= 29.4C/W, TB= 100.7-29.4*1.04= 70.1C

    I appreciate your feedback. Thanks

  • Hello Mojtaba, 

    Of course, I am happy to answer any questions you may have. 

    Yes, these values are due to the assumptions made in the JEDEC thermal standard. For RthetaJC (junction-to-case (top)) and RthetaJB (junction-to-board) these assume that heat is only dissipating from the top of the case (RthetaJC) and heat is only dissipating from the bottom of the case (RthetaJB). While the PSI-JT and PSI-JB values assumes that heat dissipates from all the device surfaces as well as the board. In short, the PSI values typically are more accurate temperature measurement, but in order to use them a final board temperature is required. In this case, it likely that the die sits closer to the bottom of the board. 

    Can you help verify that your Power dissipation is 1.04W?

    In addition, the TPCB value needs to be measured from an actual board this cannot be an estimate in order to use PSI values. If this is not available for an approximation, use the RthetaJA values. Please see additional section from the thermal app notes below explaining when to use each equation and how to calculate. 

    Thank you, 

    McKyla

  • McKyla,

    Power dissipation comes from page 6 of the component datasheet. I have taken the difference of voltage 1.3V and multiplied it by Iout of 0.80. I have assumed Vinx*Ig to be negligible. The only measurement that I have is the case temperature 96C. I do not have the ambient measured around the device but could be above 68C. What i need to know is the junction and board temp estimates. how would yo do it if you were me? Thanks. 

    Mojtaba

  • Hey Mojtaba, 

    What is your Vin, Vout, Iout in your system? This is maximum dropout and maximum Iout of the device, but typically we do not use this value. Typically, we use maximum values that are expected to be on the device, not the max of the device. 

    Thank you, 

    McKyla

  • McKyla, I do not have these values measured. wouldn't using the max values gives the most conservative results? Thanks. 

  • Hello Mojtaba, 

    Yes, but this is not realistic at all since 1.04W on an LDO is quite a lot, typically, much lower power dissipation is expected. Do you have a schematic or what Vin, Vout, Iout do you expect? 

    Thanks, 

    McKyla

  • Good Morning McKyla,

    Good Point! unfortunately, all I have is the case (top) and ambient temp. All I want to do is to get an estimate of the junction and board temp in an existing test and see if it works in a different application. Please let me know if the following makes sense. 

    Tj = Ta + Pd * RθJA    Eq1

    Tj = Tc = Pd * ψJT       Eq2

    Equate Eq1 and Eq2 and solve for Pd. Please note that Ta, Tc are known. RθJA and ψJT come from datasheet

    Now, Tb is found from:

    Tb = Tj – Pd * ψJB

    Do you see any issues with this procedure? Thanks

  • Good afternooon Mojtaba, 

    I hope you are having a great day!

    Yes, while you can use Tj = Tc + (Pd *ψJT) to find the theoretical max Pd this will not be realistic for what the LDO can handle, because this is under ideal conditions. In addition, the board layout can change the thermal capabilities of the device by 30-50% and is the largest factor in thermal resistance other than (Vin-Vout)*Iout. This device is quite robust, so it can handle a lot of power dissipation for an LDO. The 1.04W of power dissipation should be okay for this device to handle with a board that is the same or better than the JEDEC board. 

    Hopefully this helps a little to give an estimate, also keep in mind that this device's recommended Tj is 125C. 

    Thank you, 

    McKyla

  • Thank you McKyla, 

    I am not worried about the device handling the load and the junction temperature will always be much lower than 125C. It is just that a NTC chip installed on the board monitors the board temp and triggers a warning message at 83C and a fault message at 88C. My intension was to get the board temp estimate when the board were in a different application. Most if not all of your customers use your products in a different environment than what these thermal metrics were developed. This should not stop your customers from using these metrics to estimate parameters in their own designs. There was a time in my past life when I designed heatsinks for major telecommunication companies. My colleagues and I always used manufacturers thermal metrics knowing that the application environment might have been different than Ideal under which thermal metrics were developed. Why? Because these data were all we had and without them we would be working in a vacuum. Cheers!

  • Hey Mojtaba, 

    Yes, definitely understood here. We do always use estimates and understand that under any different circumstances there might be some difference. Texas Instruments always uses JEDEC standard to simulate thermal metrics. Good luck in your design! 

    Thank you, 

    McKyla