Hi TI Support,
The TPS7A94 datasheet states that I_CL will be 100% if the parallel impedance of the R_FB network is less than 12.5k (sampled during startup).
I understand that picking 12.4k for the R_FB_PG(bottom) (as recommended in the datasheet and here) does guarantee this. But for the sake of BoM consolidation, I would like to pick 10k for the bottom resistor and calculate R_FB_PG(top) accordingly.
For I_CL=100% and PG threshold=~95% I would use:
- for V_out(nom)=1.2V: R_FB_PG(top) = 47k
- for V_out(nom)=3.3V: R_FB_PG(top) = 147k (=100k+47k)
Question 1:
- Would the above R_FB_PG(top) values work for the specified use-cases?
If I understand correctly, creating a correct R_FB_PG voltage divider network is not only important for correct PG pin function (which may be of no concern if the user doesn't need PG output), but is rather critical for the IC to determine the finalization of the startup procedure and hence for stable operation.
About the divider network in the EVM:
In the EVM, both resistors of the R_FB_PG network are 10k. This raised my confidence that 10k as the bottom resistance should work just fine. However, I am still puzzled by the following statement in the EVM datasheet::
"... with R3 and R7 set to 10 k, and with the programmable current limit set to 100% of ILIMIT, the PG pin goes up when the output voltage reaches 50% of the targeted value."
Following the formula in the IC datasheet, picking 10k for both resistors with V_out(nom)=3.3V should result in a PG threshold of ~12.1%×V_out(nom).
So, question 2:
- Can you please explain the EVM datasheet statement, or is this a typo?
Thank you very much for your help!
Best regards,
Mark