I need a clarification / some reassurance regarding bq2403x and its standby feature (CE pin). Note: I do not own an EVM.
I have a use case where there may be no battery connected; in which case I would like USB or AC to be powering the system through the OUT pin (basically, I want the system to use any available power source). For this to work, the datasheet seems to suggest that CE needs to be HIGH:
"The bqTINY III-series enters the low-power standby mode when the CE input is low with either AC or USB present. In this suspend mode, internal power FETs Q1 and Q3 (see Figure 4) are turned off [...]"
However, a prior forum post seems to mention that the system would always be powered, even if CE state is LOW:
"You are correct in that the BQ24035 will not "totally" shut down when the CE pin disables the chip. It was designed to intelligently manage the power sources that are available so that there would always be at least one source of power available to the system. "
The reason I'm asking is I would like a more elegant way to get power at OUT, rather than using two diodes to generate a HIGH for CE (as in the EVM), when a battery is not present (if a battery were present, it'd power OUT no matter the state of CE). I have no need for ever pulling CE to LOW, so I figured I'd tie it to OUT; however if there's no OUT voltage because CE is low and there's no battery, this may not work (as the datasheet suggests, see first quote above) (chicken and egg problem); however, the forum post (see second quote above) makes me think that it'd work. So which is it, can I avoid the two diodes that are in the EVM? Are there any counter-indications to tying CE, PSEL and ISET2 to the system side (OUT)? Why isn't the EVM doing this instead of adding diodes to the BOM? Did I miss this information from the datasheet?
Thanks in advance for any insight!