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LM53602: The datasheet Figure 21. Efficiency

Part Number: LM53602
Other Parts Discussed in Thread: LM53603AEVM

Hi all

Would you mind if we ask LM53602?

On the datasheet Figure 21. Efficiency, it shows efficiency = 87% in case of Output current=10mA with Vin=18V, Vout=5V and Inductor = XAL6030-222ME.
We tried to realize it, however the result of simulation on Webench was approx 75%.
When we choice the incductor 6.8uH, we can get efficiency = 84%.

So, could you let us know constants of L, Cout, Cin and others which you simulated on the datasheet Figure 21. Efficiency?
We would like to know how to get over efficiency=87% with with Vin=18V, Vout=5V, Output current=10mA and Inductor = 2.2uH.
We appreciate your help always.

Kind regards,

Hirotaka Matsumoto