The output voltage range0.6-6V.Now my output voltage is 8V.there is no problem.Also, The input voltage range is 6-36V,why the output voltage is so low.
I would like to know the risk when I output voltage is 8v.
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I talked to some engineers and there are some additional points I can give you.
The device might be able to operate with your requirements, nevertheless functionality is not guaranteed.
1. Thermal limits
Be sure that thermal limit is not exceeded. The maximum junction temperature is 150C. The device will go into thermal shutdown at 165C and will turn on again with a hysteresis of 15C (see datasheet point 6.5.). So you have to make sure that your application provides enough cooling capacity.
2. Current limits
The current limit section in the datasheet (refer to section 7.3.4.) says that current is sensed through the low side FET and the high side FET.
The overcurrent shut off for the low side is 13A and for the high side is 16A as typical values.
Depending on your input voltage and switching frequency you have different ripple currents. I calculated some for you.
These are peak to peak values in ampere. So depending on your conditions you might reach current limit and the device turns off.
The following picture shows you as an example the current through the low side FET with 20V input, 8V output @ 360kHz switching frequency.
With this conditions or some other conditions, the current limit might be triggered (13A is a typical value, it can be slightly below).
You can use the Power stage designer tool to calculate these values and it also gives you some graphs. Perhaps this can help you.
Here is the link: www.ti.com/.../powerstage-designer stage designer&tisearch=Search-EN-Everything
3. Stability
Stability could also be a problem.
It might be the case that your line regulation is not the best. So your output voltage of 8V could swing by some mV.
Also the load regulation could be problematic, so that your output jumps, when a load transient occurs.
This behavior can be tested with the EVM and you can decide, if the performance is god enough for your desired application.
Hopefully these points help you.
Best regards,
Michael
Dear Michael,
Thanks for your answer.Now I have another problem, that is, when I put the output voltage of 5V, the outut short circuit and then open and found that there will be 100us output of more than 10V.
Best regards,
Shaopeng