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REG101: Powering sensors using LDO for precise voltage

Neeraj Rai
Prodigy 100 points
Part Number: REG101

I need to power a few sensors with 3V. The current consumption for one sensor is less than 12 mA. I need to provide voltage as precise as possible as a deviation of supply voltage from the rated input voltage would also cause wrong output. I am using a mcu which can provide current upto 800 mA at its 3V3 pin. I want to use the 3V version of REG101 (connected to 3V3 of the mcu) to power the sensors. Now, though the dropout voltage mentioned is 60 mA, the datasheet also mentions that min. VIN should be VOUT+0.4V. Could I use this regulator for this application or should I go for any other LDO?

  • 0
    TI__Guru 55940 points
    Hi Neeraj,

    The minimum Vin of Vout + 0.4 V is the minimum test condition used for the Electrical Characteristics table specifications. As such, if you choose to use REG101 with a lower Vin, the regulator may not meet the specifications depicted in the datasheet.

    One thing that you will want to keep in mind for any LDO in this application is that when the LDO starts up, there will be inrush to charge the output capacitor(s). You will want to make sure that your MCU is able to not only handle the load current plus LDO ground current, but also the inrush current.

    Very Respectfully,
    Ryan