Other Parts Discussed in Thread: CSD95490Q5MC,
Hi,
Similar to the question in: https://e2e.ti.com/support/power-management/f/196/t/663588
1. I'm looking for the Rlset equation for CSD95492QVM, does it match the equation in the link above for CSD95490Q5MC?
2. Our design uses 330nH for a main power rail (278kOhm from above equation), and 4700nH for a lower current auxiliary rail (both using CSD95492QVM for part reuse). For the larger value inductor, the calculated Rlset is >700MOhm, I assume open circuit is the correct solution here?
Thanks for your help!
Regards,
Cam.