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LP38853: Reverse current

Part Number: LP38853

Dear all.

Please teach me about reverse current.
Reverse currrent is written in the data sheet as follows.
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The NMOS pass element, by design, contains no body diode.
This means that, as long as the gate of the pass element is not driven, there is no reverse current flow through the pass element during a reverse voltage event.
The gate of the pass element is not driven when VBIAS is below the UVLO threshold, or when the EN pin is held low.
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When EN is High and UVLO exceed the threshold, does a reverse current flow?

Is the MOSFET back to back coupling?

Regards,
PAN-M

  • Hi PAN-M,

    Yes, a reverse current will flow under the following conditions:

    • The output voltage exceeds the input voltage
    • The output voltage is not being held at the regulation output by a downstream component
    • EN is high
    • UVLO exceeds the threshold

    This is because EN and BIAS enable and power the internal control loop, allowing it to respond to changes in the output voltage. If the input voltage drops below the output, and the output is not held up, the output voltage will also drop as the output capacitor discharges. The control loop attempts to continue regulating by driving the gate of the pass FET to the BIAS voltage. However, since the input voltage is lower than the output voltage, driving the gate forces the pass FET to conduct in the reverse (OUT to IN) direction until the output capacitor is fully discharged. This behavior is explained in the last paragraph of the Reverse Voltage Feature Description in the datasheet:

    The power n-channel MOSFETs are not back to back coupled as one of the main advantages of using n-channel pass FETs is the ability to achieve very low dropout voltages. Adding another FET in series for back to back coupling would increase the dropout voltage. Although the pass FETs for this device have the same gate drive, they are not in series; the sources of the MOSFETs are tied together. This can be seen in the functional block diagram:

    Thanks,

    Gerard

  • I was able to understand your comment.
    Thank you.
    PAN-M