Team,
In the ISO5451-Q1 datasheet on chapter: 7.8 Safety Limiting Values, it says that total dissipated power should not exceed 1.255W. Is that because internal isolator structure would suffer? As a resulting question, how to limit power supply current? One way would be to place resistors on power supply pins. But it will cause voltage drop. Is there some better but still simple way to do current limit?
Thanks for your help
TI Customer
Your comment "TI's series capacitive isolation is reinforced, and thus when a failure occurs you will still be left with basic isolation" implies that a user need not worry about a failure because basic isolation remains intact.
In other words, the mA and mW numbers Section 7.8 of the ISO5451 datasheet can be exceeded, because worst case basic isolation is intact. This is your meaning?
7.8 Safety Limiting Values
Safety limiting intends to minimize potential damage to the isolation barrier upon failure of input or output circuitry. A failure of the I/O can allow low resistance to ground or the supply and, without current limiting, dissipate sufficient power to overheat the die and damage the isolation barrier, potentially leading to secondary system failures
