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TL760M33-Q1: TL760M33-Q1 will be extremly hot

Part Number: TL760M33-Q1
Other Parts Discussed in Thread: LM2596, TPS62177

I use the TL760M33-Q SMD on our new design. I use an 0.1uF on input and and a22uF on 3.3 Volt out. The Part reaches over 100 degrees temperture. Is this normal?
Maybe i use a special thermal management?

  • Hi Remo,

    The power dissipated within a linear regulator will raise the temperature of the regulator.  The power dissipated within the regulator is:

    Pd = (Vin - Vout) x Iout

    Depending on your application's power dissipation, ambient temperature, and layout it is possible to for the regulator temperature to reach 100 C.

    It is important to note that the primary heatsink for the regulator is the PCB copper.  In particular for TL760M33-Q1 the primary heatsink is the GND copper local to the regulator.  As such the PCB layout will have an impact on the thermal performance of the regulator.  The following Application Report discusses the impact on board layout on a linear regulator's thermal performance:

    http://www.ti.com/lit/an/slvae85/slvae85.pdf

    Very Respectfully,

    Ryan

  • Many thanks for the Answer Ryan.
    Sorry i think i am wrong with my idea to use an LDO for create 3.3 Volts.
    I forget to say i use a 21 Volt Battery to convert the 3.3 Volt Value.
    Maybe is a Step Down Regulator the correct solution? Can you a part from TI recommend.
    Input Voltage 16-23 Volt
    Power consumption 300 - 400 mAh
    single output 3.3 Volt
    Price and external parts no matter. But i don't like extreme temperature on the pcb.
    Former i use the LM2596 and this part works perfect for 5 Volt. But it can be a little smaller 

    Best regards

    Remo

  • Hi Remo,

    The TPS62177 is a very simple and small DC/DC that meets your specs.