Hello. I'm planning to use a TI TPS61235P boost converter IC for an upcoming project (VOUT 5V/3.5A with a VIN_min of 3V). In the features TI mentions there are two 10A internal power switches for the synchronous function but in the headline it's mentioned as a 8A converter, where does this descripency come from?
Also, the minimum value for I_LIM (switch valley current limit) is 6.5A. With an output of 5V at 3.5A, with a VIN of 3V the input current roughly be about (assuming 85% efficiency) 6.86A. This should work, according some of the efficiency plots I think this is doable with this IC but what is confusing me is the minimum value of I_LIM at 6.5A. Does this mean I should only draw 6.5A max at the input (since the IC can have this limit at the temperature extremes it seems)?
In short, I'm not understanding how the 10A, 8A and the 6.5A are related.