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TPS54040A: Inverting Buck Boost

Part Number: TPS54040A
Other Parts Discussed in Thread: TPS54040

Hi Team,

I have a customer who is trying to build an inverting buck boost with the TPS54040A and is having some issues with it:

(Vin = 15V, Vout =  -5V, 1.5MHz switching frequency)

-5V runs without load, but with a 12 ohms resistor (417mA load) the voltage breaks down after around 10 seconds. This could be something thermal although after rough calculation with the datasheet parameters I do not see how the junction temperatures can reach 180 ° C.

In Application Report SLVA317B in equation (5), Dmax is included in the Iomax calculation - can you explain that to me? With 110mA ripple I might be pretty much on the limit of what is acceptable.

When I remove the load, the voltage does not come back. I have to turn Vin on / off. After I short the capacitor on the SS the voltage recovered (without load).

So summarized-

Can you explain why Dmax has to be taken into account for negative voltages of the maximum current calculation? Do you have an explanation why the -5V Buck circuit does not recover from an overload. And how can I fix it?

Circuit diagram of the -5V circuit is attached.

  • Hello Mihir,

    The TPS54040 is hitting current limit and will not be able to supply 400mA.

    The equation 5 is right.  Another way of calculating the peak current on a buck boost inverter is as follows.

    IL average = Iin + Iout

    ILpeak = IL Average + Iripple/2

    Assume Iripple = 110mA

    Iin = Pin/Vin

    Pin = Pout/Eff

    Assume Eff = 85%

    Pout = Vout * Iout

    Pout = 5V * 0.4A = 2W

    Pin = 2.353W

    IIn = 157mA

    IL Average = 0.4+0.157A = 0.557A

    IL peak = 0.558A+0.055A = 0.612A peak

    This would be slightly worse at 412mA (assumed 400mA is example above) The minimum peak current limit assuming 85% efficiency  for the TPS54040 is 0.6A so you are on the threshold of current limit.

    Suggest using a 1A device for you application if you have a requirement of 0.5A. 

    Hope this helps?