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LMR14050-Q1: Component value questions

Part Number: LMR14050-Q1
Other Parts Discussed in Thread: LMR14050

The value of the output inductor of a switching regulator is greatly affected by the output current.  I first sized the inductor based on the max LMR14050 output current of 5A.  However, if based on the most expected use of say 1A the inductor is 5 to 7 times larger which costs a lot more and takes up much more board space.  Guessing it more prudent I went with the higher value.  How much would it matter?  That is, is it worse to run a high current through a larger than spec inductor or low current through a smaller than spec inductor?

Second, the regulator's input voltage from a rectified AC supply filtered through bulk capacitance varies continuously.  The voltage on the capacitors will drop linearly (ignoring the high frequency on/off saw tooth tiny variances) until it is less than the AC driving voltage.  This can take roughly 1/2 to 2/3 of each cycle and the differences are not small.  I calculate that with a 5A load current the input voltage will vary from about 16V to 25V over a half-cycle or so.  My question is what V-in should be used in calculations, the peak which lasts maybe 0.1% of the time, or maybe the average, or what?

  • Hello Rod,

    I suggest you chose the inductor value based on the max output current.  The suggested value is based on a ripple current of 20% to 40% the output current.  in your case select an inductor based on 1A to 2A ripple current respectively.  This will ensure that the selected inductor value is low and the size of the inductor is kept relatively small.

    I would use the maximum Vin for your design, assuming that the frequency of the AC rectified input is much lower than the switching frequency of the converter.

    Hope this helps?