I was hoping for some help regarding the 100% duty-cycle operation of the TPS62148 for 5V output.
1) Figure 80 from the DS shows around 700kHz switching frequency before the graph ceases (device enters 100% duty-cycle mode?)
- This is about 1.5us period. The Duty cycle (per 9.4.3 from DS) is VOUT/VIN, so at 5.3V, would be 94%. The off time is then around 80ns.
From the DS, this is the value given for minimum off-time.
Thus, any input voltage lower than this will cause the device to operate in 100% duty-cycle mode, correct?
2) The DS states:
The high-side switch stays turned on as long as the output voltage is below the internal set point.
What is the internal set point? Is this the output voltage set-point with the FB resistors? In other words, at 100% duty-cycle, if the input voltage increases, the output voltage will increase, and if the output voltage goes higher than the "set" output voltage, switching operation begins again?
3) As Vin decreases, switching frequency decreases...until duty cycle is high enough that the minimum off-time of 80ns is met, and the device enters 100% duty-cycle mode. Once in this 100% duty-cycle mode, can it withstand long-periods of time in this operation?
4) Is there a way to calculate the switching frequency as it decreases related to lower input voltage? Equations 3) and 4) are for TON time given a set, non-changing switching frequency, so I was wondering how the Figure 80 frequency could be calculated...?
Regards,
Darren