Hi,
Please tell me how to calculate the junction temperature when the output is short-circuited.
Customer conducted an output short circuit test under the following conditions.
However, the device did not undergo a thermal shutdown.
・Vin=13.5V
・Vout=0V
・TA=25℃
・Short-circuit current=104mA
I understand that the loss calculation of LDO is the following formula.
・Pd=Vin×Ishort=1.4W
・θJA=206℃/W
・Junction temperature rise ≒ 289℃
However, the thermal protection and protections did not destroy the device.
Could you tell me how to calculate QJ when output short circuit condition?
And In this short-circuit test, what is the state inside the LP2985 to protect it, and what is the junction temperature at that time?
Best regards,
Yusuke