Hello,
Is the two of I2C slave address in the datasheet (0x60 / 0x61) shown as 7-bit? If so, they should be 0xC0 / C2 in 8-bit respectively, correct?
Regards,
Kazuto
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Hello,
Is the two of I2C slave address in the datasheet (0x60 / 0x61) shown as 7-bit? If so, they should be 0xC0 / C2 in 8-bit respectively, correct?
Regards,
Kazuto
Hi Kazuto,
The addresses shown (0x60/0x61) are the 7-bit address, and the 8th bit in the transaction is the read/write bit. Frequently, an I2C function is called which takes the 7-bit address and read/write as inputs, and concatenates these 2 pieces of information to transmit as an 8-bit packet. If you are including the read/write bit as the LSB of the 8-bit address, then you are correct that the 8-bit address including the read/write bit is 0xC0/0xC2
Hi Kazuto,
I'm going to mark this thread as "TI Thinks Resolved". If you have any follow up questions here, please feel free to open the thread again.