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TPS7A20: Enable Pin Implementation in Hardware Design

UTKARSH P
Expert 1175 points
Part Number: TPS7A20
Other Parts Discussed in Thread: TPS7A49, TPS7A30

Hello All,

We have decided to use TPS7A2033PDBVR LDO IC as voltage regulator as we have A supply voltage of  6V and we want to regulate it to 3.3V which is used to power up the MCU.

After referring the data sheet we understood that we have to give a high signal at this pin to the ("VEN")enable pin of the regulator to enable the its output. 

As this regulator itself is used to regulate voltage for MCU we cannot provide high using MCU. So please suggest me with solution for my issues mentioned below,

1. So how can i give High input to the ("VEN") enable pin of regulator?

2. After referring similar kind of regulator viz. TPS7A49 and TPS7A30 we understand that the power supply signal (6V in our case) is given to both ("VIN") input pin and ("VEN") enable pin,

  • Can i use the same configuration? (i.e., 6V power supply output directly is connected to ("VIN") input pin and ("VEN") enable pin).

       OR

  • Should i use a voltage divider?

Please Help at the earliest

Thanks and Regards 

Utkarash

  • 0
    TI__Genius 13085 points

    Hi Utkarash,

    Since it doesn't seem like you need to independently control Ven then our recommendation would be to connect Ven to Vin as this is the simplest solution. Since the rising threshold for Ven is less than the rising UVLO the LDO will turn on once Vin/Ven exceeds the UVLO rising threshold. 

    The only reason to use a voltage divider would be if you want to delay the turn on of the LDO, such as waiting until the input voltage is above the nominal output voltage. Similarly you could use a voltage divider to turn off the LDO at a certain point when the input voltage is falling. Keep in mind that there is hysteresis in the enable circuit and so the turn on and turn off points will be different. To ensure that the LDO is enabled Ven>=Min Ven(hi) and to ensure that the LDO is disabled Ven<Max Ven(low).