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TPS61087: How to calculate Inductor current spec?

Part Number: TPS61087

Hi TI ENG team

I want to know how to calculate inductor current spec.

My design spec is 

1) Vin=+3.0V~+4.2V, => li-ion battery 1-cell

2) Vout = +7.5V

3) Iout = 0.3A

4) Fsw=1.2MHz

5) n=0.9(90%), ripple=0.35(35%)

I calculated inductor value(Eq 5, datasheet 13page)

Vin @+3.0V =>  5.14uH

Vin @+4.2V =>  7.39uH

I choose 8.2uH. Is it right?

But I don't know 8.2uH current spec.

Do i have to choose 3.2A switch current? I can't find Equation.

Because If Inductor have a high current spec, Inductor size is bigger.

Thank you