Hi TI ENG team
I want to know how to calculate inductor current spec.
My design spec is
1) Vin=+3.0V~+4.2V, => li-ion battery 1-cell
2) Vout = +7.5V
3) Iout = 0.3A
4) Fsw=1.2MHz
5) n=0.9(90%), ripple=0.35(35%)
I calculated inductor value(Eq 5, datasheet 13page)
Vin @+3.0V => 5.14uH
Vin @+4.2V => 7.39uH
I choose 8.2uH. Is it right?
But I don't know 8.2uH current spec.
Do i have to choose 3.2A switch current? I can't find Equation.
Because If Inductor have a high current spec, Inductor size is bigger.
Thank you