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Cheap isolated 24V 0.1A DC-DC converter

Other Parts Discussed in Thread: LM5017, LM5018, LM5019, LM25017, LM25019, LM25018

Hello,

I am designing a data logger for 16 sensors, and I need to power sensors separately from isolated power supplies (each supply must be isolated from each other).

Now I need to design the sensors' supplies, and I need some help.

Requirements:

- my power source is a 24VDC

- the sensors have to be powered at 24V and the maximum load of each sensor is 100 mA (@24V)

- budget limitations: the total BOM cost for the single sensor supply should be under € 3 for 100 pcs (that means, for 16 sensors each board, the need to buy a total of 1600 identical circuits); this is not a strict limit, but I cannot go much higher than that

- the design should be as small as possible

- I need some kind of Enable pin (or something similar... but, well, I could use an input MOSFET to do that, if I find a suitable solution missing the EN pin)

- I need to measure the output current, but this has to be done on the input side; as I don't have strict requirements on the current accuracy, I can also estimate the circuit efficiency in order to have a better value...

My problem is I never designed an isolated power supply; I gave a look at many flyback switching regulators data sheets, as well as at other solutions...

I finally found LM5017, which seems to be a good solution. I also found PMP7315, which is a reference design apparently meeting all my requirements in terms of output specifications.

Now I have some questions about it:

- Can I use the UVLO input as an enable pin?

- How can I measure the output current? Looking at the PMP7315 schematics, I was thinking about putting a small precise resistor in series to the inductor in the non-isolated side, and using an opamp + MCU's ADC to read the current... but I don't know if that resistor can somewhat alter the circuit.

- How accurate is PMP7315 output? I mean, LM5017 is a buck converter, and the transformer is 1:1; that should mean I cannot get Vin = Vout... or am I missing something?

- Can I use LM5018 or LM5019 with the very same circuit to save money?

- And what about LM25017, LM25018 and LM25019?

Many thanks in advance for your help.

Stefano Infante