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LDO Noise SLYY076 Application Note

Hello,


I have some question about the application note slyy076 about LDO noise.

I don't understand the equation 6 page 7. It seems not according to the text explaination because I don't see any average in this equation.

More of that, could you explain in details how you make the graphical integration by dividing by the frequency?

Is it possible to detailed the explaination and how to pass to the equation?

Thanks

Matthieu Baque

  • Hi Matthieu,

    Wow, this is kinda embarrassing but looking at it I see that equation 6 is incorrect. You'd think that after reading and re-reading your own white paper so many times it would be free of such mistakes. Below is the equation that should have been in the paper (and I'll work on having it updated so it's correct). 

    In order to "graphically integrate" the noise we are performing a midpoint Riemann sum (see the illustration bellow for an example). To determine the midpoint (vertically) we add the two noise measurements (which requires them to be squared individually since they are assumed to be uncorrelated and Gaussian) and then divide by 2. to get the area of the rectangle we then multiply by the width of the rectangle which is the change in frequency between the two measurements. We add all of these rectangles and then take the square root of that to get the RMS Noise.

    Let me know if any of that isn't clear or if you have any other questions, and like I said I'll work on getting the white paper updated. 

    -Kyle Van Renterghem

  • Hi Kyle,

    Thanks a lot for your feedback.

    It's almost clear right now. The only point not very clear is the explaination about why you have to square each measurements indivdually before to add it.

    Is it to make like an average quadratic?

    If you can detaileda little this part but perhaps, I have to take a glance on the midpoint Rienmann sum for this point.

    Matthieu Baque

  • Hi Kyle,

    Like I said, the only point that isn't very clear is the square. More than a quadratic average, Is it to have a power instead of voltage?

    Could you just detailed this part or give me a link with an app note to explain that, plesae?

    Many thanks

    Matthieu Baque

  • Hi Matthieu,

    Sorry for the delay in getting back to you. You hit on it in your last post, RMS values are the quadratic average. Since noise is uncorrelated and random we can't simply add two noise voltages together, we must take the RMS value instead.

    If it's easier to think about it you can think about it in terms of units: We measure noise in uV/(Hz^1/2), you square that and it gives you (uV^2)/Hz, dividing by two doesn't change the units, multiplying by the change in frequency gives you uV^2 and taking the square of that gives you uV (of course that should be denoted uVrms). 

    -Kyle

  • Thanks a lot Kyle

    Matthieu Baque