Hi, team.
Why are VDIG1 and VDIG2 different from other LDO in start-up?
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Natasha-san
I'm using TPS65910AA1 and AM335x processor.
The attached waveform is EVM, but there is same waveform in the application.
This can be checked very easily.
Best Regads,
Kobayashi
Kobayashi-san,
The slope of the start up waveform is related to the capacitance and current on the pin. On the TPS659108EVM, all these lines have the same capacitance. Thus, the current supplied to the pins is most likely the differentiating factor. VDIG1 and VDIG2 are supplied by VCC6, while VMMC and VAUX33 are supplied by VCC3.
If you look at the TPS659108EVM User Guide, there is a schematic of the board that shows all these pins. On this schematic, it shows that VCC3 and VCC6 both use jumpers to determine how the pins are supplied with power. Depending on the settings of the jumpers on the board, there will be different amounts of current supplied.
Thus, you can move the jumpers on the EVM to change how the power is being sourced and change the slope of the waveforms you are seeing on power up. Below is the schematic for reference. The highlighted jumpers are the ones affecting the slopes on the waveforms you attached. The blue circles indicate the options you have to source those pins.
Best Regards,
Nastasha
Kobayashi-san,
After working through this in the lab, it seems that this may be the result of the inherit architecture of the device. I have attached my waveforms for your reference. When zoomed in, these waveforms (VDIG1, VAUX33, VMMC in that order) have the same slope qualities as your scope shot. The only difference is the start up timing - VMMC rises before VAUX33, rather than at the same time.
Please let me know if you are experiencing any further troubles or concerns.
Thanks,
Nastasha