I currently design the LM5088QMH-1 device for power design.
VIN = 25V to 70V
Vout = 24V
Iout = max. 10A
Fsw = 580 kHz
As designing according to the design example shown in the datasheet,
It is difficult to derive the value of RAMP Resistor and leave a question.
On page 22, I would like to design as Rramp = (Vvcc - Vramp) / (Ios - 25uA).
Ios = Vout x 5uA/V = 24V x 5uA/V = 120uA/V
I can get it.
The Vvcc value, as shown on page 6,
Vvcc(reg) = typ. 7.8V at Vvcc = open
Can I apply a value?
In addition, the Vramp value, as seen on page 7,
Cycle-by-cycle current Limit Delay = typ. 280ns at Vramp=2.5V
If so, is Vramp = 2.5V?
I would appreciate your feedback on how to obtain the Rramp value.
Thank you.