For one question,
We use 10UH inductor in TPS61046 circuit, and we have encountered that input peak current will go up to 680mA when the loading is coming.
After we changed inductor to 1UH,the input peak current would go down to 330mA. I checked the datasheet,it gave the formula on page 12.
IL(P)=IL(DC)+ΔIL(P-P)/2
ΔIL(P-P)=Vin*(Vout+0.8V-Vin)/L*fSW*(Vout+0.8V)
From the formula,if L is bigger,ΔIL(P-P) will be smaller,and the inductor peak current IL(P) will be smaller, but we see the opposite result.
Can you help to explan the principle and give us suggestion?
the other question,
Whether the output voltage is fully controlled by feedback,I mean it will not give a bigger voltage than we set in any time,whether it is possible to output a 28V voltage although we just set the output voltage to 9V?
our customer worried about boost circuit,if this situation happen,the voltage will cause the loading device damaged.please help to confirm