Hello all,
I could find current limit at 70A and thermal shutdown at 150 degree.
When I calculate Junction temp with instruction on the datasheet,
Tj = Temp + 32.6 * I * I * Ron
= 25 + 32.6 * 20 * 20 * 8m
= 170
When peak current is 20A, Junction Temp is over than shutdown limit.
Cannot the current be over than 20A?