Hi team,
When no battery is present in the circuit, the waveforms of SYS voltage and BAT voltage is shown as follows. At t0, the charger begins to charge the BAT capacitor. And the voltage of BAT capacitor rises rapidly to about 4.2V. After about 250ms, the charger goes to termination status. Then the SYS voltage and BAT voltage starts to drop due to leakage current. After 250ms, the new charge cycle begins.
I have two questions about above phenomene.
1. At t0, the voltage of BAT capacitor has already been 4.2V and charge current is lower than termination current. So the charge status should end at t0 rather than t1. Why? Is there any delay time?
2. At t2, the charger begins to recharge BAT capacitor. I think the recharge cycle should begin when Vbat drops about 100mV rather than 600mV shonw in following waveforms. Why? Is there any delay time?
Thanks a lot!
Naizeng wang
