This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

LM4040: LM4040 vs. LM4040-N

Part Number: LM4040

Hello,

What is the difference between LM4040 and LM4040-N? Both have same fixed output options, and the rest of the specifications appear to be almost identical.

Thanks in advance,

Leo

  • Hi Leo,

    Texas Instruments and National Semiconductor pre-merger created a LM4040 device. After the merger, to differentiate the devices, we added a "-N" to specify which originated from National for customers that were originally using that device. While both do offer similar specifications, they do also offer some differences in options offered. For example we offer the LM4040-N in AEC Q100 automotive grade but we do not for the LM4040.

    -Marcoo Z
  • Hi Marcoo,

    Thank you for the quick response. This is for a new design, and the application is not automotive. Based on that, would you recommend one part over the other?

    Leo
  • Hi Leo,

    LM4040-N is the more popular one of the two and it has more accuracy options.
    Is this reference going to power an ADC?
    What are your design requirements?
    Lets first find out if the LM4040 is the family to use.

    -Marcoo Z
  • Hi Marcoo,

    Yes, this is for a 12-bit ADC. As for requirements, 0.5% initial tolerance is adequate, commercial temperature range, power consumption is not critical.

    Leo
  • Hi Leo,

    The LM4040-N family would be a good device for 12-bit ADCs. For example in the ADC12048 12-bit ADC, the LM4040-N is the recommended voltage reference.

    The first part of the orderable number would be LM4040CI (where C is 0.5% and I is -40C to 85C). This device does not have a commercial (0C to 70C) temperature range variant but the industrial variant works just as well.

    The only things missing would be the output voltage of the voltage reference and package. for output voltage, I would choose a voltage that is greater but as close as possible to your the full scale signal.

    -Marcoo Z
  • Thank you, Marcoo. I appreciate your help in clearing this up for me.

    Best Regards,
    Leo