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LMZ12002: Can't get 6-7.5V if Vin = 11V

Part Number: LMZ12002

Hello, i want to get from LMZ12002 VOUT=6-7v IOUT>1.5A with VIN=11v and i have problem.
I have only 4.5 VOUT ... I can't get VOUT>4.5V, my schematics is attached.
I think this is my mistake and LMZ 12002 needs more drop voltage. 
If i change VIN to 15V i have calculated VOUT...
Big quantity of PCB's is ready, i can't change pcb... :(
I can change any components (include LMZ12002) to other pin to pin components if it will be help.
if you have any solution or minds, write it please...

  • Hi Aleksei,

    What is your desired switching frequency? I had a look on the Ron resistor value, which is 4.7kOhm. Is that correct?

    The datasheet says that the On-resistor has to be in the range between 25kOhm and 124kOhm. Because of this I did some calculations.

    Probably you hit the minimum ON time limit or the minimum OFF time limit.

    The  typical datasheet values for these are:

    - tmin ON: 150ns (typical) ; 200ns (+30% headroom for my calculations)

    - tmin OFF 260ns (typical) ; 350ns (+30% headroom for my calculations)

    Refering to page 17 of the datsheet (Ron resistor selection), I checked some values.

    - Based on the resistor divider on the FB pin, your desired output voltage is 6.8V. With an input voltage of 11V, his gives me a Duty cycle of 62%.

    - Assuming you hit the minimum ON time: 0.62=200ns/(200ns+tmin OFF) --> tmin OFF = 122ns  

    This value is lower than the value in the datasheet. So the device is not able to approach the desired Duty cycle of 62%.

    - Assuming, you reach the minimum OFF time: 0.62=ton/(ton+350ns) --> tmin ON = 571ns

    571ns + 350ns = 921ns which gives you switching frequency of 1.08MHz (this is the max frequency to reach with this device)

    Now you can calcite the ON time resistor: Ron = Vout/(1.3*10^-10 * fsw) = 6.8V/(1.3*10^-10*1.08MHz) = 48.2kOhm

    Hope this can help you in fixing your issue. Please don't hesitate to contact me again, in case there are questions left.

    Best regards,

    Michael

  • You are right. RON is not correct, it is my mistake! Thank you very much for answer and for really fast support. 
    Now it is work correctly!