The table description shows values for external LO of 0x15 and internal LO div2 of 0x19 but there are only 4 bits in the field. What is the correct value for each mode?
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Hi Ken,
The table is correct.
There are other reserved modes.
Regards,
Vicente
It is not 5 bits
The GUI is off compared to the rest of the bits I see your confusion but when you choose an option you will see in the bottom left what actually gets written .
For example if user chooses external LO (15) what gets written is 0x0F00 which is correct.
Regards,
Vicente