Other Parts Discussed in Thread: DRV5056
Tool/software:
Hi,
What is the recommended position/placement of the sensor DRV5056 for current measurement?
What is the expected reading for the above two placements?
Thanks,
Ravi
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Tool/software:
Hi,
What is the recommended position/placement of the sensor DRV5056 for current measurement?
What is the expected reading for the above two placements?
Thanks,
Ravi
Ravi,
Thanks for your question. If using this device to measure current, the magnetic field vector needs to be oriented from the bottom of the package towards the top.
The field produced by a current carrying wire follows the right hand rule.
So for placement, the sensor needs to be offset horizontally somewhat from the current in order to result with a vertical magnetic field component. Additionally, it would likely require that the current through the wire be quite large in order to produce a strong enough field to produce a measurable effect.
The field is calculated with this equation
B = μ0I/(2πr)
Where:
If your currents are not large enough to create a measurable field using the DRV5056, I would recommend you check out these devices which route the current you are trying to measure through the package and are specifically designed to measure current:
https://www.ti.com/sensors/magnetic-sensors/products.html#-3=Hall-effect%20current%20sensors&
Thanks,
Scott
Hello Ravi,
Thanks for considering to use Texas Instruments. As the device detects field magnitudes normal to the top surface and b fields travel in loops around current carrying traces, you should put the device to the side of the current path in plane with it. Close to the current path is best. However, unless you are sensing a lot of current the field might not be strong enough for good snr.
Hello Patrick & Scott,
Appreciate the response, but my question is with respect to sensor orientation.
In both the options, the current direction is same. But the sensor orientation was different.
As the sensor is unipolar and responds to only south pole of magnetic flux density.
In which option the sensor detects the signal (current path is same)?
Thanks,
Ravi
Ravi,
Since the sensor is sensitive to the field in the direction normal to the PCB surface (out of page), the rotation of the sensor will not impact the results. However, running the current immediately beneath the sensor where the arrow is indicating will produce a horizontal field at the sensor location.
To create a positive vertical component based on the direction of the current, you will need the sensor to the left of the current carrying trace/wire.
Thanks,
Scott
Hi Scott,
The direction of the current flow is on top of the sensor, i.e., the sensor was placed in parallel with other PCB where the trace will be in parallel with the sensor as mentioned earlier.
When measured the sensor output for both the options, the results are different.
Option 1: The sensor output voltage is 0.65V
Option 2: The sensor output voltage is -0.55V
Thanks,
Ravi
Hi Scott,
The direction of the current flow is on top of the sensor, i.e., the sensor was placed in parallel with other PCB where the trace will be in parallel with the sensor as shown below.
When measured the sensor output for both the options, the results are different.
Option 1: The sensor output voltage is 0.65V
Option 2: The sensor output voltage is -0.55V
Thanks,
Ravi
Ravi,
The Hall-element location of this sensor is located in the center of the package.
If your current trace is offset to the left or right of this, then there will be some vertical component. Your result for option #1 seems to imply you are not receiving any input since the Quiescent output voltage for this device is 0.6-0.65V.
I'm a bit unsure of your option #2 results. The device should not be able to drive the output voltage below GND. When you probe this output voltage it will be most accurate to measure as physically close to the device pins as possible. If a negative field is applied, there may be some headroom to enable driving the output somewhere between 0-0.6V, but the voltage should remain above 0V.
Thanks,
Scott
Hi Scott,
Sorry for the typo. The sensor voltage for option#2 is 0.55V.
When there is no current, the measured sensor output is 0.6V.
When the current applied, the sensor output is 0.65V for option#1 and 0.55V for option#2.
Thanks,
Ravi
Ravi,
It sounds as though there is just a very small amount of vertical field and that by rotating the setup you move the sensing element slightly to either side of your current carrying trace. Sensor output #1 is getting a positive field, and sensor output #2 is getting a negative field. You'll want to be on the same side as in sensor output #1.
Testing with the sensor shifted further to the side may be an informative test to see if you can get a stronger response on the output. However, I fear that if you move too far that you may not actually observe an increase in output response. While the vector will become more vertical, your field strength is inversely proportional to the distance from the wire and you'll have less field to work with.
Thanks,
Scott