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DRV5032: current consumption, conditions for peak current

Genius 14280 points
Part Number: DRV5032

Hi all

Please find a question from my customer copied below.

Can you clarify what the conditions / duration for the 2mA pk current are ? .... is this a pk current at startup ?

Best regards

Ueli

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We re-read the DRV5032AJ datasheet, it states 2 mA peak current, which’s beyond our design using low power NFC energy harvesting. But I don’t see the peak current, though we load the sensor with cap.

 I saw only one thread on this question online, Link, where TI advised to design with the max current. Sweat smile

 Can you advise me in what conditions the peak current happens?

  • Ueli,

    Thank you for reaching out with your question.  The peak current should occur per the timing diagram in the datasheet

    The device will periodically sample the Hall Element which requires forcing current in order to produce a measurable effect.  So, about every 50 ms (when sampling at 20 Hz) there will be a short duration rise in Icc to allow for the sample.  After this is complete the current consumption will return to the nominal low state.  On average the current consumption should always be less than 3.5 uA as shown in the electrical table. The datasheet indicates that the active time (tactive) for each sample lasts about 40 us

    Your system needs to be able to supply the 2 mA peak current which might occur during the sample period.  Depending on your supply capacitance, you may find this very short current peaking difficult to observe.

    Any load current would be additional to this requirement.  Your output capacitor would only draw extra current during output transitions, and when the device is driving low you should expect current draw through the pull-up resistor.

    Thank you,

    Scott Bryson

  • Scott

    Thank you for the quick reply and for the detailed explanation.

    So I assume this peak current would be provided by the decoupling capacitor and it would therefore not be seen when measuring the input current to the circuit.

    Best regards

    Ueli