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AWR1642BOOST: Angle resolution : object separation at 80 m range to show them as different trackers

Part Number: AWR1642BOOST
Other Parts Discussed in Thread: AWR1642

We are using AWR1642 in SRR/USRR mode

We understand from other queries and documents that objects will be resolved in angle FFT , if there at the same range and with same velocity . From AWR1642 specification we understand that angle resolution is 15 degrees in SRR/USRR mode . 

From the pic x1= 80*tan(7.5) which comes to 10.5 m

So objects have to be separated by atleast 21 m at 80 m distance to show as two separate trackers ? let us know if our understanding is correct .

  • Hi,
    Sorry for delayed response.
    Let us check and get back to you.

    Regards,
    Jitendra
  • Hi Shravaan,

    Your understanding is correct. If there are two objects traveling at the same relative velocity (w.r.t the radar) at the same distance then they have to be separated by at least the angular resolution to be seen as two different objects.

    Note that, when I say the 'same' relative velocity, I mean that the difference in radial-velocities of the targets are within the velocity resolution of the chirp design. When I say the 'same' distance, I mean that the difference in the radial-range is within the range-resolution.

    For the tracker to miss one of these objects, both objects have to maintain the same radial velocity and the same range for an extended period of time. This is improbable. Hence, in most cases, the SRR TI design is able to resolve objects that are closer than the angular resolution.

    A common case where the above assumptions fail is if the targets and the radar are both stationary. In such a case, if there are two objects at the same range (from the radar), they will remain at the same at that range indefinitely, and as such cannot be distinguished by the radar.

    Regards

    Anil

  • Thank you for the detailed explanation Jitendra .