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Part Number: TIDA-01063
I am looking at the TIDA-01063 reference design (document TIDUBV4A) as a starting block for developing an over current sensor in the DC leg of a half bridge high frequency inverter. I will need a PCB Rogowski coil and an integrator circuit. I was trying to follow the formulas in document TIDUBV4A. I see the physical dimensions of the Rogowski coil in Table 1 (Page 2) (coil inner and outer radius, number of turns, etc.). Then on page 8, equation 9, I see the formula for mutual inductance. According to Table 2, page 14, that inductance is .048 uh. The dimension for h (dist between upper and lower trace of the PCB) is not listed in Table 1 so I am having a hard time reconciling the formula to give .048 uh. If I assume an h = 1.255 mm I can get 48 uh but that is far off and very high inductance. Can someone please help me out with this? The formula I'm using is M=(N x (uh)/(2pi))xln(Dext/Dint). Maybe I don't have it right.
Thank you - John
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Thanks for using our reference design for your application, we will be glad to support to you in your design.
As per your above query my understanding is that your are trying to build current sensing for high frequency half bridge AC-DC inverter helping to achieve isolated current measurement using existing PCB itself. I assume your are trying to record average current through leg for control scheme.
For 174 turns, 1.7 mm (0.0017 m) PCB height and inner radius of 12.5 mm (0.0125 m) and outer radius of 27.7 mm (0.0277 m) we get mutual inductance of 47.07 nH approximated to 48 nH with actual measurement. (Convert mm to meter for computation as permeability is Henry per meter)
In reply to Srinivasan Iyer:
In reply to John Currie:
We verified the self inductance using inductance analyzer and used used peak observed observed value out of 10 PCB coil sensor for doing step response simulation to get worst case delay.
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