Hello. This is a question regarding the gain stage mentioned on page 9 of the TIDA-01351 document.
The formula of gain is 10*[R2/Rth+R1]
Is [R2/Rth+R1] correct?
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The text states in 126.96.36.199, Summing Circuit and Gain Stage section, "... the Thevenin equivalent of all summing resistor R (1 kΩ; see Figure 3) is Rth 120 Ω (see Figure 4). This Rth (120 Ω), R1 (887 Ω), and R2 (10 kΩ) forms a gain of 10 [R2 / (Rth + R1)]."
It looks like a comma was left out of the text after "forms a gain of 10" resulting in a gain equation that incorrectly places a 10x multiplier in front of the resistor relationship. In actuality, when you apply the Rth, R1 and R2 values and leave the "10" out before the resistor equation you obtain a gain of about 10 V/V which is correct:
G (V/V) = [R2 / (Rth + R1)] = [10 kΩ / (120 Ω + 887 Ω)] = 9.93 V/V or about 10 V/V.
The gain equation that you stated is correct.
Precision Amplifiers Applications Engineering