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CC2652P7: 3.3V to 1.8V Power Supply/Ferrite Bead with Peripherals

Part Number: CC2652P7

In a scheme like below, does it really matter if a peripheral uses the 1.8V vs. VDD bus for power? If I'm reading correctly, the LaunchPad puts the external flash on the bus before VDD (i.e. before the ferrite bead). Looking for any insight.

  • Hi Matt,

    To clear up a few things:

    1. The node labeled "1.8V" is actually the external power supply path which in our reference design is called "WMCU_VDD" and your VDD would be our VDDS. Both are typically 3V or 3.3V. Additionally, only one is used and not both meaning you would select WMCU_VDD if you want the launchpad to be powered externally or VDDS if you want it to be internally powered via USB. See image below.

    2. We typically do not use 1.8V for the voltage supply as it is too close to the brown-out voltage, which is 1.7V and would render the device non-functional if the voltage is not held steady.

    3. The P10 header is where you would use a jumper to toggle between an external or internal power supply. See image below.

    Let me know if you have anymore questions.

    Best regards,

    Bun