CC2640R2F: How to reduce the current consumption of CC2640 during Advertising.

I am using BLE project Zero application example and i want to reduce the current consumption during advertising. currently i have set "#define GAP_ADV_TX_POWER_NO_PREFERENCE  " to "0",  and advetising parameters are default except the advertising interval, i have set it to 10 sec. with this parameters the device is consuming 6.1 mA peak during advertising and the duration of the advertising is 6.021ms. i want to reduce this current consumption. is there any way. can i reduce the TX power to reduce the consumption or is there any other  way also.

#define GAP_ADV_TX_POWER_NO_PREFERENCE      0

#define GAPADV_PARAMS_LEGACY_SCANN_CONN {                                  \
  .eventProps = GAP_ADV_PROP_CONNECTABLE | GAP_ADV_PROP_SCANNABLE |        \
                GAP_ADV_PROP_LEGACY,                                       \
  .primIntMin = 16000,                                                       \
  .primIntMax = 16000,                                                       \
  .primChanMap = GAP_ADV_CHAN_ALL,                                         \
  .peerAddrType = PEER_ADDRTYPE_PUBLIC_OR_PUBLIC_ID,                       \
  .peerAddr = { 0xaa, 0xaa, 0xaa, 0xaa, 0xaa, 0xaa },                      \
  .filterPolicy = GAP_ADV_WL_POLICY_ANY_REQ,                               \
  .txPower = GAP_ADV_TX_POWER_NO_PREFERENCE,                               \
  .primPhy = GAP_ADV_PRIM_PHY_1_MBPS,                                      \
  .secPhy = GAP_ADV_SEC_PHY_1_MBPS,                                        \
  .sid = 0                                                                 \
}